PHYSICS
HIGH SCHOOL

Answer: C is correct answer.

Harmonious is a design has equal weight on both sides, it's said to have harmonious balance.

Hope it helped you.

-Charlie

Harmonious is a design has equal weight on both sides, it's said to have harmonious balance.

Hope it helped you.

-Charlie

Answer:

Answer:

harmonious

Explanation:

COLLEGE

Waves hitting at an angle and then bending around features of the coast is known as

Waves hitting at an angle and then bending around features of the coast is known as Wave refraction

When waves hitting a specific angle, some part of the waves will be closer to the shallow part of the water and some part will be closer to the deeper part of the water, which makes the wave became somehow bent around the shore.

When waves hitting a specific angle, some part of the waves will be closer to the shallow part of the water and some part will be closer to the deeper part of the water, which makes the wave became somehow bent around the shore.

MIDDLE SCHOOL

A body of mass 1kg suspended from the free end of a spring having force constant 400N/m is executing S.H.M when the total energy of system is 2 joule find the minimum acceleration

Answer:

-30 m/s²

Explanation:

The total energy is the sum of the gravitational potential energy of the mass, the kinetic energy of the mass, and the elastic energy in the spring.

∑E = PE + KE + EE

∑E = mgh + ½ mv² + ½ kx²

At the bottom, h = 0 and v = 0.

∑E = ½ kx²

2 = ½ (400) x²

2 = 200 x²

0.01 = x²

x = 0.1

At the top, v = 0 and x = 0.1 − h.

∑E = mgh + ½ kx²

2 = (1) (10) h + ½ (400) (0.1 − h)²

2 = 10h + 200 (0.01 − 0.2h + h²)

2 = 10h + 2 − 40h + 200h²

0 = 200h² − 30h

0 = 10h (20h − 3)

h = 0.15

So x ranges from -0.05 m to 0.10 m.

Sum of forces on the mass:

∑F = ma

kx − mg = ma

The minimum acceleration is when x is a minimum.

(400 N/m) (-0.05 m) − (1 kg) (10 m/s²) = (1 kg) a

a = -30 m/s²

The maximum acceleration is when x is a maximum.

(400 N/m) (0.1 m) − (1 kg) (10 m/s²) = (1 kg) a

a = 30 m/s²

And of course, acceleration is 0 when kx = mg.

(400 N/m) x = (1 kg) (10 m/s²)

x = 0.025 m

HIGH SCHOOL

Determine the frequency of light whose wavelength is 4.257 x10-7 cm

Frequency x Wavelength = Speed of light Now, speed of light = 3 x 10^5 km/s = 3 x 10^8 m/s = 3 x 10^10 cm/s Frequency = speed/Wavelength = (3 x 10^10)/(4.257 x 10^-7) =7 x 10^16 Hz

HIGH SCHOOL

Which quantity in the equation E=MC^2 represents the speed of light? A. C.//

//B. S.

//C. M.

//D.E.

HELP FAST!!!!!!

The answer is A. C. The equation has C, which is Speed of light squared

The answer to your question is A : C