PHYSICS COLLEGE

A 20kg boy stands on a small stationary (at rest) merry-go-round near the edge of the merry-go-round. The total moment of inertia of the system of merry-go-round with the boy on it about the center is 120kg m2 . The boy at the edge of the merry-go-round (radius of 2m) jumps off the merry-go-round in a tangential direction with a liner speed of 1.5m/s. What is the angular speed of the merry-go-round after the boy leaves it?

Answers

Answer 1
Answer:

Answer:

The angular speed of the merry-go-round after the boy leaves it is 2.25 rad/s.

Explanation:

Given that,

Mass of boy = 20 kg

Total moment of inertia = 120 kgm²

Radius = 2 m

Speed = 1.5 m/s

We need to calculate the moment of inertia of boy

Put the value into the formula

We need to calculate the

Using conservation of angular momentum

Put the value into the formula

Hence, The angular speed of the merry-go-round after the boy leaves it is 2.25 rad/s.


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Which of the following is the correct SI unit to use in measuring amount of material contained in a solid sphere? A. kilograms
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The correct SI unit to be used for measuring the amount of material in a solid sphere would be kilograms. Kilograms are officially the base unit of mass, and other measurements such as pounds in the imperial system are defined in terms of kilograms.
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COLLEGE

When tuning his guitar, a music student notices that the string is not vibrating at the desired frequency of 120 Hz, so he tightens the string by 15.5% to get this frequency. At what frequency was the string vibrating when he first started the tuning process

Answers

Answer:

Explanation:

We know that

frequency ∝ √ Tension

So

Δn / n = 1/2 (ΔT / T)

Δn / n = .155 / 2 ( GIVEN )

= .0775

Δn  = .0775 n

Let the original frequency be n

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n + .0775 n = 120

n = 111.36

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Answers

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